A man is 24 years older than his son. After two years, his age will be twice the age of his son. The present age of his son is:

A man is 24 years older than his son. After two years, his age will be twice the age of his son. The present age of his son is:

  • (A) 14 years
  • (B) 18 years
  • (C) 20 years
  • (D) 22 years
  • Solution: Let's assume the present age of the son to be x years.
  • The present age of the man would, therefore, be (x + 24) years.
  • Two years later, the son’s age would be (x + 2) years.
  • The man’s age two years later would be (x + 24 + 2) = (x + 26) years.
  • We are given that the man’s age two years later would be twice the son’s age two years later.
  • Thus, the equation to be solved is:
  • (x + 26) = 2(x + 2)
  • Solving the equation, we have:
  • (x + 26) = 2(x + 2)
  • => x + 26 = 2x + 4
  • => 26 - 4 = 2x - x
  • => 22 = x
  • Thus, the present age of the son is 22 years.
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Related MCQs:

 ‘NATO’ is an abbreviation of:

  • (A) North Atlantic Treaty Organization
  • (B) Non-Aligned Treaty Organization
  • (C) Non-Aligned Trading Organization
  • (D) North American Transport Organization

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